6x-5(1-2x)=-8(1-2x)+3

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Solution for 6x-5(1-2x)=-8(1-2x)+3 equation: 



6x-5(1-2x)=-8(1-2x)+3

We move all terms to the left:

6x-5(1-2x)-(-8(1-2x)+3)=0

We add all the numbers together, and all the variables

6x-5(-2x+1)-(-8(-2x+1)+3)=0

We multiply parentheses

6x+10x-(-8(-2x+1)+3)-5=0



We calculate terms in parentheses: -(-8(-2x+1)+3), so:

-8(-2x+1)+3

We multiply parentheses

16x-8+3

We add all the numbers together, and all the variables

16x-5

Back to the equation:

-(16x-5)



We add all the numbers together, and all the variables

16x-(16x-5)-5=0

We get rid of parentheses

16x-16x+5-5=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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