6x-5(x-2)=12-3(x-4)

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Solution for 6x-5(x-2)=12-3(x-4) equation: 



6x-5(x-2)=12-3(x-4)

We move all terms to the left:

6x-5(x-2)-(12-3(x-4))=0

We multiply parentheses

6x-5x-(12-3(x-4))+10=0



We calculate terms in parentheses: -(12-3(x-4)), so:

12-3(x-4)

determiningTheFunctionDomain
-3(x-4)+12

We multiply parentheses

-3x+12+12

We add all the numbers together, and all the variables

-3x+24

Back to the equation:

-(-3x+24)



We add all the numbers together, and all the variables

x-(-3x+24)+10=0

We get rid of parentheses

x+3x-24+10=0

We add all the numbers together, and all the variables

4x-14=0

We move all terms containing x to the left, all other terms to the right

4x=14

x=14/4

x=3+1/2

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