6x-7/1-2x=x+40/x-8

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Solution for 6x-7/1-2x=x+40/x-8 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

6*x-(2*x)-(7/1) = x+40/x-8 // - x+40/x-8

6*x-(2*x)-x-(40/x)-(7/1)+8 = 0

6*x-2*x-x-40*x^-1-7+8 = 0

3*x^1-40*x^-1+1*x^0 = 0

(3*x^2+1*x^1-40*x^0)/(x^1) = 0 // * x^2

x^1*(3*x^2+1*x^1-40*x^0) = 0

x^1

3*x^2+x-40 = 0

3*x^2+x-40 = 0

DELTA = 1^2-(-40*3*4)

DELTA = 481

DELTA > 0

x = (481^(1/2)-1)/(2*3) or x = (-481^(1/2)-1)/(2*3)

x = (481^(1/2)-1)/6 or x = (-(481^(1/2)+1))/6

x in { (-(481^(1/2)+1))/6, (481^(1/2)-1)/6} 

x in { (-(481^(1/2)+1))/6, (481^(1/2)-1)/6 }

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