6x-8(6x-2)+10=12(2-x)-22-6x

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Solution for 6x-8(6x-2)+10=12(2-x)-22-6x equation: 



6x-8(6x-2)+10=12(2-x)-22-6x

We move all terms to the left:

6x-8(6x-2)+10-(12(2-x)-22-6x)=0

We add all the numbers together, and all the variables

6x-8(6x-2)-(12(-1x+2)-22-6x)+10=0

We multiply parentheses

6x-48x-(12(-1x+2)-22-6x)+16+10=0



We calculate terms in parentheses: -(12(-1x+2)-22-6x), so:

12(-1x+2)-22-6x

determiningTheFunctionDomain
12(-1x+2)-6x-22

We add all the numbers together, and all the variables

-6x+12(-1x+2)-22

We multiply parentheses

-6x-12x+24-22

We add all the numbers together, and all the variables

-18x+2

Back to the equation:

-(-18x+2)



We add all the numbers together, and all the variables

-42x-(-18x+2)+26=0

We get rid of parentheses

-42x+18x-2+26=0

We add all the numbers together, and all the variables

-24x+24=0

We move all terms containing x to the left, all other terms to the right

-24x=-24

x=-24/-24

x=1

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