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6x/20x=x
We move all terms to the left:
6x/20x-(x)=0
Domain of the equation: 20x!=0We add all the numbers together, and all the variables
x!=0/20
x!=0
x∈R
-1x+6x/20x=0
We multiply all the terms by the denominator
-1x*20x+6x=0
We add all the numbers together, and all the variables
6x-1x*20x=0
Wy multiply elements
-20x^2+6x=0
a = -20; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·(-20)·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*-20}=\frac{-12}{-40} =3/10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*-20}=\frac{0}{-40} =0 $
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