6x/x-3-x-3/x+3=9/9-x2

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Solution for 6x/x-3-x-3/x+3=9/9-x2 equation: 



6x/x-3-x-3/x+3=9/9-x2

We move all terms to the left:

6x/x-3-x-3/x+3-(9/9-x2)=0



Domain of the equation: x!=0

x∈R





Domain of the equation: 9-x2)!=0

We move all terms containing x to the left, all other terms to the right

-x2)!=-9

x!=-9/1

x!=-9

x∈R



We add all the numbers together, and all the variables

-(-1x^2+9/9)+6x/x-x-3/x-3+3=0

We add all the numbers together, and all the variables

-(-1x^2+9/9)-1x+6x/x-3/x=0

We get rid of parentheses

1x^2-1x+6x/x-3/x-9/9=0

Fractions to decimals

1x^2+6x/x-3/x-1x+1=0

We multiply all the terms by the denominator


1x^2*x+6x-1x*x+1*x-3=0

We add all the numbers together, and all the variables

1x^2*x+7x-1x*x-3=0

Wy multiply elements

x^3-1x^2+7x-3=0

We do not support expression: x^3

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