6x2+-98x+72=0

Solution for 6x2+-98x+72=0 equation:

6x^2+-98x+72=0

We add all the numbers together, and all the variables

6x^2-98x=0

a = 6; b = -98; c = 0;
Δ = b2-4ac
Δ = -982-4·6·0
Δ = 9604
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9604}=98$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-98)-98}{2*6}=\frac{0}{12}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-98)+98}{2*6}=\frac{196}{12}
=16+1/3
$