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6x2+10x+4=0

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Solution for 6x2+10x+4=0 equation:



6x^2+10x+4=0
a = 6; b = 10; c = +4;
Δ = b2-4ac
Δ = 102-4·6·4
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
x_{1}=\frac{-b-\sqrt{\Delta}}{2a}
x_{2}=\frac{-b+\sqrt{\Delta}}{2a}

\sqrt{\Delta}=\sqrt{4}=2
x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2}{2*6}=\frac{-12}{12} =-1
x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2}{2*6}=\frac{-8}{12} =-2/3

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