6x2+10x+4=7/8

Solution for 6x2+10x+4=7/8 equation:

6x^2+10x+4=7/8

We move all terms to the left:

6x^2+10x+4-(7/8)=0

We add all the numbers together, and all the variables

6x^2+10x+4-(+7/8)=0

We get rid of parentheses

6x^2+10x+4-7/8=0

We multiply all the terms by the denominator


6x^2*8+10x*8-7+4*8=0

We add all the numbers together, and all the variables

6x^2*8+10x*8+25=0

Wy multiply elements

48x^2+80x+25=0

a = 48; b = 80; c = +25;
Δ = b2-4ac
Δ = 802-4·48·25
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-40}{2*48}=\frac{-120}{96}
=-1+1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+40}{2*48}=\frac{-40}{96}
=-5/12
$