If it's not what You are looking for type in the equation solver your own equation and let us solve it.
6x^2+10x-24=0
a = 6; b = 10; c = -24;
Δ = b2-4ac
Δ = 102-4·6·(-24)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-26}{2*6}=\frac{-36}{12} =-3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+26}{2*6}=\frac{16}{12} =1+1/3 $
| Y=|x-3| | | -6b=8-5b | | 15*y=2055 | | 9-z=8z-9 | | 5x+-2=7x-6 | | 3(2x+11=6x+4 | | 3-(5-2x)=-1-6x | | -5y=-4-4y | | G(3)=|-3x-1| | | -=10x | | 7/4w-7/3=-5/3w-1 | | -5+2p=-4p+7 | | 24=7y+10 | | -5(4a+7)=105 | | 5x^2-20x-1=13x+13 | | 25x2-70x+49=0 | | 0=16x^2-28x+174 | | 8x-12=2x+3(2x-4) | | 5x+8=x+1 | | 9-5g=-2g | | 4p+7=-9-2p | | 2x+7=1x+12 | | -99=9(u-4) | | -3u=10-5u | | x-4(2x+9)=4-7x | | 2r=10+3r | | 5(5x+2)=1x+12 | | 1/4y-6=1/9y | | -4f-9=-7f | | (21.75)(23.34)=7X+5(x+4)+6x+10(x+7)+15(x+7)+123.5 | | 4b=4b+16+26 | | 8(2k+5)+5k=0 |