6x2+10x-6=4x+4

Solution for 6x2+10x-6=4x+4 equation:

6x^2+10x-6=4x+4

We move all terms to the left:

6x^2+10x-6-(4x+4)=0

We get rid of parentheses

6x^2+10x-4x-4-6=0

We add all the numbers together, and all the variables

6x^2+6x-10=0

a = 6; b = 6; c = -10;
Δ = b2-4ac
Δ = 62-4·6·(-10)
Δ = 276
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{276}=\sqrt{4*69}=\sqrt{4}*\sqrt{69}=2\sqrt{69}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{69}}{2*6}=\frac{-6-2\sqrt{69}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{69}}{2*6}=\frac{-6+2\sqrt{69}}{12}
$