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6x^2+11x=8
We move all terms to the left:
6x^2+11x-(8)=0
a = 6; b = 11; c = -8;
Δ = b2-4ac
Δ = 112-4·6·(-8)
Δ = 313
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{313}}{2*6}=\frac{-11-\sqrt{313}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{313}}{2*6}=\frac{-11+\sqrt{313}}{12} $
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