6x2+13x-14=0

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Solution for 6x2+13x-14=0 equation:



6x^2+13x-14=0
a = 6; b = 13; c = -14;
Δ = b2-4ac
Δ = 132-4·6·(-14)
Δ = 505
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{505}}{2*6}=\frac{-13-\sqrt{505}}{12} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{505}}{2*6}=\frac{-13+\sqrt{505}}{12} $

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