If it's not what You are looking for type in the equation solver your own equation and let us solve it.
6x^2+16x=0
a = 6; b = 16; c = 0;
Δ = b2-4ac
Δ = 162-4·6·0
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-16}{2*6}=\frac{-32}{12} =-2+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+16}{2*6}=\frac{0}{12} =0 $
| x/2+x/4+30=180 | | A+(b-19)÷2=111 | | 3(3x+1)=2x+18 | | 12=-4(—6x-3) | | -6y+17=3y-2 | | A+b-19=111÷2 | | 7n-2(n+5)=n-16 | | 9-p/2=-1 | | X²–y+4=0 | | 5-3g=-22 | | 2v-9=23 | | A+b-19=111 | | 65=3y+8 | | -5-4x=2x+31 | | 7n-4(2n+5)=n-16 | | 4.2+x=-5.9 | | 6+2n+2=-20 | | 29=y/3-13 | | 5x+12=-15 | | 34=5y-16 | | 8y+3y=-22 | | -2/3*d=-4/5 | | X=(5-3x)=7x+4 | | -4/5+(-1/4=c | | -j+3j=-6 | | 3c=-7F | | 2w+(1241/2+2w)=41/2 | | X+7y=69 | | t=6+4.85 | | -17q=-6.54-17.6q | | 8(4x-7)+5=29 | | x/3-18=(-28) |