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6x^2+17x-88=0
a = 6; b = 17; c = -88;
Δ = b2-4ac
Δ = 172-4·6·(-88)
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2401}=49$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-49}{2*6}=\frac{-66}{12} =-5+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+49}{2*6}=\frac{32}{12} =2+2/3 $
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