6x2+21x=17

Solution for 6x2+21x=17 equation:

6x^2+21x=17

We move all terms to the left:

6x^2+21x-(17)=0

a = 6; b = 21; c = -17;
Δ = b2-4ac
Δ = 212-4·6·(-17)
Δ = 849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-\sqrt{849}}{2*6}=\frac{-21-\sqrt{849}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+\sqrt{849}}{2*6}=\frac{-21+\sqrt{849}}{12}
$