6x2+23x+7=0

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Solution for 6x2+23x+7=0 equation:



6x^2+23x+7=0
a = 6; b = 23; c = +7;
Δ = b2-4ac
Δ = 232-4·6·7
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-19}{2*6}=\frac{-42}{12} =-3+1/2 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+19}{2*6}=\frac{-4}{12} =-1/3 $

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