6x2+24x-840=0

Solution for 6x2+24x-840=0 equation:

6x^2+24x-840=0

a = 6; b = 24; c = -840;
Δ = b2-4ac
Δ = 242-4·6·(-840)
Δ = 20736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{20736}=144$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-144}{2*6}=\frac{-168}{12}
=-14
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+144}{2*6}=\frac{120}{12}
=10
$