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6x^2+27x-15=0
a = 6; b = 27; c = -15;
Δ = b2-4ac
Δ = 272-4·6·(-15)
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1089}=33$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-33}{2*6}=\frac{-60}{12} =-5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+33}{2*6}=\frac{6}{12} =1/2 $
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