6x2+28x-208=0

Solution for 6x2+28x-208=0 equation:

6x^2+28x-208=0

a = 6; b = 28; c = -208;
Δ = b2-4ac
Δ = 282-4·6·(-208)
Δ = 5776
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5776}=76$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-76}{2*6}=\frac{-104}{12}
=-8+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+76}{2*6}=\frac{48}{12}
=4
$