6x2+37x+45=0

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Solution for 6x2+37x+45=0 equation:



6x^2+37x+45=0
a = 6; b = 37; c = +45;
Δ = b2-4ac
Δ = 372-4·6·45
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-17}{2*6}=\frac{-54}{12} =-4+1/2 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+17}{2*6}=\frac{-20}{12} =-1+2/3 $

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