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6x^2+6x=1940448
We move all terms to the left:
6x^2+6x-(1940448)=0
a = 6; b = 6; c = -1940448;
Δ = b2-4ac
Δ = 62-4·6·(-1940448)
Δ = 46570788
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{46570788}=\sqrt{324*143737}=\sqrt{324}*\sqrt{143737}=18\sqrt{143737}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-18\sqrt{143737}}{2*6}=\frac{-6-18\sqrt{143737}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+18\sqrt{143737}}{2*6}=\frac{-6+18\sqrt{143737}}{12} $
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