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6x^2+7x-98=0
a = 6; b = 7; c = -98;
Δ = b2-4ac
Δ = 72-4·6·(-98)
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2401}=49$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-49}{2*6}=\frac{-56}{12} =-4+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+49}{2*6}=\frac{42}{12} =3+1/2 $
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