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6x^2+8x-28=2x^2+4
We move all terms to the left:
6x^2+8x-28-(2x^2+4)=0
We get rid of parentheses
6x^2-2x^2+8x-4-28=0
We add all the numbers together, and all the variables
4x^2+8x-32=0
a = 4; b = 8; c = -32;
Δ = b2-4ac
Δ = 82-4·4·(-32)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-24}{2*4}=\frac{-32}{8} =-4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+24}{2*4}=\frac{16}{8} =2 $
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