6x2-0.2x-0.48=0

Solution for 6x2-0.2x-0.48=0 equation:

6x^2-0.2x-0.48=0

a = 6; b = -0.2; c = -0.48;
Δ = b2-4ac
Δ = -0.22-4·6·(-0.48)
Δ = 11.56
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.2)-\sqrt{11.56}}{2*6}=\frac{0.2-\sqrt{11.56}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.2)+\sqrt{11.56}}{2*6}=\frac{0.2+\sqrt{11.56}}{12}
$