6x2-12x-504=0

Solution for 6x2-12x-504=0 equation:

6x^2-12x-504=0

a = 6; b = -12; c = -504;
Δ = b2-4ac
Δ = -122-4·6·(-504)
Δ = 12240
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{12240}=\sqrt{144*85}=\sqrt{144}*\sqrt{85}=12\sqrt{85}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-12\sqrt{85}}{2*6}=\frac{12-12\sqrt{85}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+12\sqrt{85}}{2*6}=\frac{12+12\sqrt{85}}{12}
$