6x2-13x+4=0

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Solution for 6x2-13x+4=0 equation: 



6x^2-13x+4=0

a = 6; b = -13; c = +4;
Δ = b2-4ac
Δ = -132-4·6·4
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-\sqrt{73}}{2*6}=\frac{13-\sqrt{73}}{12}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+\sqrt{73}}{2*6}=\frac{13+\sqrt{73}}{12}
$

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