If it's not what You are looking for type in the equation solver your own equation and let us solve it.
6x^2-19x-18=0
a = 6; b = -19; c = -18;
Δ = b2-4ac
Δ = -192-4·6·(-18)
Δ = 793
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-\sqrt{793}}{2*6}=\frac{19-\sqrt{793}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+\sqrt{793}}{2*6}=\frac{19+\sqrt{793}}{12} $
| 5x2-12x-11=0 | | 18x2-13x+7=0 | | 18x2-13x+17=0 | | 13x2+13x-14=0 | | 20x2+6x-15=0 | | 113.04=(3.14)r(r) | | 20x2-6x+15=0 | | 15x2+11x+8=0 | | 15x2-11x-8=0 | | 8x2-7x-18=0 | | 19x2-12x-8=0 | | 9x2-18x-3=0 | | x+74+x+8+x+67+x+27=360 | | x+47+93+x+58=360 | | 5(3x-2x)=7x+4 | | (4d^4-15d^2+5d+6)y=0 | | 7-5x=10x+2 | | 3y+12=32 | | 2x-4=10x+7 | | 5x+3(x+4)=36+4x | | 96/k=3k= | | 3x+(3-2)=10 | | 9x-3=123x= | | 15+bb=6 | | 18z=-18+20z | | 6-2(c-3=12 | | -17k-10=18-13k | | -3g=-5g+4 | | -3g=5g+4 | | 2x2-20+46=0 | | 2x^2-20+46=0 | | 1/6(3/2j-4)+j=2/3j |