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6x^2-2=34-x
We move all terms to the left:
6x^2-2-(34-x)=0
We add all the numbers together, and all the variables
6x^2-(-1x+34)-2=0
We get rid of parentheses
6x^2+1x-34-2=0
We add all the numbers together, and all the variables
6x^2+x-36=0
a = 6; b = 1; c = -36;
Δ = b2-4ac
Δ = 12-4·6·(-36)
Δ = 865
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{865}}{2*6}=\frac{-1-\sqrt{865}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{865}}{2*6}=\frac{-1+\sqrt{865}}{12} $
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