6x2-2x=1

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Solution for 6x2-2x=1 equation:



6x^2-2x=1
We move all terms to the left:
6x^2-2x-(1)=0
a = 6; b = -2; c = -1;
Δ = b2-4ac
Δ = -22-4·6·(-1)
Δ = 28
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{28}=\sqrt{4*7}=\sqrt{4}*\sqrt{7}=2\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{7}}{2*6}=\frac{2-2\sqrt{7}}{12} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{7}}{2*6}=\frac{2+2\sqrt{7}}{12} $

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