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6x^2-41x-56=0
a = 6; b = -41; c = -56;
Δ = b2-4ac
Δ = -412-4·6·(-56)
Δ = 3025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3025}=55$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-41)-55}{2*6}=\frac{-14}{12} =-1+1/6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-41)+55}{2*6}=\frac{96}{12} =8 $
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