6x2-43x+73=0

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Solution for 6x2-43x+73=0 equation:



6x^2-43x+73=0
a = 6; b = -43; c = +73;
Δ = b2-4ac
Δ = -432-4·6·73
Δ = 97
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-43)-\sqrt{97}}{2*6}=\frac{43-\sqrt{97}}{12} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-43)+\sqrt{97}}{2*6}=\frac{43+\sqrt{97}}{12} $

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