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6x^2-44=0
a = 6; b = 0; c = -44;
Δ = b2-4ac
Δ = 02-4·6·(-44)
Δ = 1056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1056}=\sqrt{16*66}=\sqrt{16}*\sqrt{66}=4\sqrt{66}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{66}}{2*6}=\frac{0-4\sqrt{66}}{12} =-\frac{4\sqrt{66}}{12} =-\frac{\sqrt{66}}{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{66}}{2*6}=\frac{0+4\sqrt{66}}{12} =\frac{4\sqrt{66}}{12} =\frac{\sqrt{66}}{3} $
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