6x2-5+1=0

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Solution for 6x2-5+1=0 equation:



6x^2-5+1=0
We add all the numbers together, and all the variables
6x^2-4=0
a = 6; b = 0; c = -4;
Δ = b2-4ac
Δ = 02-4·6·(-4)
Δ = 96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{96}=\sqrt{16*6}=\sqrt{16}*\sqrt{6}=4\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{6}}{2*6}=\frac{0-4\sqrt{6}}{12} =-\frac{4\sqrt{6}}{12} =-\frac{\sqrt{6}}{3} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{6}}{2*6}=\frac{0+4\sqrt{6}}{12} =\frac{4\sqrt{6}}{12} =\frac{\sqrt{6}}{3} $

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