6x2-5x+12+3x2+4x-7=6x2-5x+12+3x2+4x-7

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Solution for 6x2-5x+12+3x2+4x-7=6x2-5x+12+3x2+4x-7 equation: 



6x^2-5x+12+3x^2+4x-7=6x^2-5x+12+3x^2+4x-7

We move all terms to the left:

6x^2-5x+12+3x^2+4x-7-(6x^2-5x+12+3x^2+4x-7)=0

We add all the numbers together, and all the variables

9x^2-(6x^2-5x+12+3x^2+4x-7)-1x+5=0

We get rid of parentheses

9x^2-6x^2-3x^2+5x-4x-1x-12+7+5=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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