6x2-800-40x-2x2=0

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Solution for 6x2-800-40x-2x2=0 equation:



6x^2-800-40x-2x^2=0
We add all the numbers together, and all the variables
4x^2-40x-800=0
a = 4; b = -40; c = -800;
Δ = b2-4ac
Δ = -402-4·4·(-800)
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{14400}=120$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-120}{2*4}=\frac{-80}{8} =-10 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+120}{2*4}=\frac{160}{8} =20 $

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