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6x^2-8=142
We move all terms to the left:
6x^2-8-(142)=0
We add all the numbers together, and all the variables
6x^2-150=0
a = 6; b = 0; c = -150;
Δ = b2-4ac
Δ = 02-4·6·(-150)
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3600}=60$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-60}{2*6}=\frac{-60}{12} =-5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+60}{2*6}=\frac{60}{12} =5 $
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