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6x^2=-x1/2
We move all terms to the left:
6x^2-(-x1/2)=0
We get rid of parentheses
6x^2+x1/2=0
We multiply all the terms by the denominator
6x^2*2+x1=0
We add all the numbers together, and all the variables
6x^2*2+x=0
Wy multiply elements
12x^2+x=0
a = 12; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·12·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*12}=\frac{-2}{24} =-1/12 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*12}=\frac{0}{24} =0 $
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