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6x^2=121
We move all terms to the left:
6x^2-(121)=0
a = 6; b = 0; c = -121;
Δ = b2-4ac
Δ = 02-4·6·(-121)
Δ = 2904
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2904}=\sqrt{484*6}=\sqrt{484}*\sqrt{6}=22\sqrt{6}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-22\sqrt{6}}{2*6}=\frac{0-22\sqrt{6}}{12} =-\frac{22\sqrt{6}}{12} =-\frac{11\sqrt{6}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+22\sqrt{6}}{2*6}=\frac{0+22\sqrt{6}}{12} =\frac{22\sqrt{6}}{12} =\frac{11\sqrt{6}}{6} $
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