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6x^2=124
We move all terms to the left:
6x^2-(124)=0
a = 6; b = 0; c = -124;
Δ = b2-4ac
Δ = 02-4·6·(-124)
Δ = 2976
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2976}=\sqrt{16*186}=\sqrt{16}*\sqrt{186}=4\sqrt{186}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{186}}{2*6}=\frac{0-4\sqrt{186}}{12} =-\frac{4\sqrt{186}}{12} =-\frac{\sqrt{186}}{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{186}}{2*6}=\frac{0+4\sqrt{186}}{12} =\frac{4\sqrt{186}}{12} =\frac{\sqrt{186}}{3} $
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