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6x^2=28
We move all terms to the left:
6x^2-(28)=0
a = 6; b = 0; c = -28;
Δ = b2-4ac
Δ = 02-4·6·(-28)
Δ = 672
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{672}=\sqrt{16*42}=\sqrt{16}*\sqrt{42}=4\sqrt{42}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{42}}{2*6}=\frac{0-4\sqrt{42}}{12} =-\frac{4\sqrt{42}}{12} =-\frac{\sqrt{42}}{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{42}}{2*6}=\frac{0+4\sqrt{42}}{12} =\frac{4\sqrt{42}}{12} =\frac{\sqrt{42}}{3} $
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