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6x^2=5x+1
We move all terms to the left:
6x^2-(5x+1)=0
We get rid of parentheses
6x^2-5x-1=0
a = 6; b = -5; c = -1;
Δ = b2-4ac
Δ = -52-4·6·(-1)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-7}{2*6}=\frac{-2}{12} =-1/6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+7}{2*6}=\frac{12}{12} =1 $
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