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6x^2=63x+195
We move all terms to the left:
6x^2-(63x+195)=0
We get rid of parentheses
6x^2-63x-195=0
a = 6; b = -63; c = -195;
Δ = b2-4ac
Δ = -632-4·6·(-195)
Δ = 8649
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{8649}=93$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-63)-93}{2*6}=\frac{-30}{12} =-2+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-63)+93}{2*6}=\frac{156}{12} =13 $
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