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6x=12(x-1/2)
We move all terms to the left:
6x-(12(x-1/2))=0
We add all the numbers together, and all the variables
6x-(12(+x-1/2))=0
We multiply all the terms by the denominator
6x*2))-(12(+x-1=0
We add all the numbers together, and all the variables
x+6x*2))-(12(-1=0
Wy multiply elements
12x^2+x-1=0
a = 12; b = 1; c = -1;
Δ = b2-4ac
Δ = 12-4·12·(-1)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-7}{2*12}=\frac{-8}{24} =-1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+7}{2*12}=\frac{6}{24} =1/4 $
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