6x=2(3x-5)+10

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Solution for 6x=2(3x-5)+10 equation: 



6x=2(3x-5)+10

We move all terms to the left:

6x-(2(3x-5)+10)=0



We calculate terms in parentheses: -(2(3x-5)+10), so:

2(3x-5)+10

We multiply parentheses

6x-10+10

We add all the numbers together, and all the variables

6x

Back to the equation:

-(6x)



We add all the numbers together, and all the variables

=0

x=0/1

x=0

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