6x=3(x-4)-x

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Solution for 6x=3(x-4)-x equation: 



6x=3(x-4)-x

We move all terms to the left:

6x-(3(x-4)-x)=0



We calculate terms in parentheses: -(3(x-4)-x), so:

3(x-4)-x

We add all the numbers together, and all the variables

-1x+3(x-4)

We multiply parentheses

-1x+3x-12

We add all the numbers together, and all the variables

2x-12

Back to the equation:

-(2x-12)



We get rid of parentheses

6x-2x+12=0

We add all the numbers together, and all the variables

4x+12=0

We move all terms containing x to the left, all other terms to the right

4x=-12

x=-12/4

x=-3

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