6x=4(4-x)=48

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Solution for 6x=4(4-x)=48 equation: 



6x=4(4-x)=48

We move all terms to the left:

6x-(4(4-x))=0

We add all the numbers together, and all the variables

6x-(4(-1x+4))=0



We calculate terms in parentheses: -(4(-1x+4)), so:

4(-1x+4)

We multiply parentheses

-4x+16

Back to the equation:

-(-4x+16)



We get rid of parentheses

6x+4x-16=0

We add all the numbers together, and all the variables

10x-16=0

We move all terms containing x to the left, all other terms to the right

10x=16

x=16/10

x=1+3/5

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