6x=62,x2

Solution for 6x=62,x2 equation:

6x=62.x^2

We move all terms to the left:

6x-(62.x^2)=0

We get rid of parentheses

-62.x^2+6x=0

We add all the numbers together, and all the variables

-62x^2+6x=0

a = -62; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·(-62)·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*-62}=\frac{-12}{-124}
=3/31
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*-62}=\frac{0}{-124}
=0
$