6y(y+2)=3y(2y-1)+27

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Solution for 6y(y+2)=3y(2y-1)+27 equation: 



6y(y+2)=3y(2y-1)+27

We move all terms to the left:

6y(y+2)-(3y(2y-1)+27)=0

We multiply parentheses

6y^2+12y-(3y(2y-1)+27)=0



We calculate terms in parentheses: -(3y(2y-1)+27), so:

3y(2y-1)+27

We multiply parentheses

6y^2-3y+27

Back to the equation:

-(6y^2-3y+27)



We get rid of parentheses

6y^2-6y^2+12y+3y-27=0

We add all the numbers together, and all the variables

15y-27=0

We move all terms containing y to the left, all other terms to the right

15y=27

y=27/15

y=1+4/5

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