6y+(y-3)=6(y+1)-3

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Solution for 6y+(y-3)=6(y+1)-3 equation: 



6y+(y-3)=6(y+1)-3

We move all terms to the left:

6y+(y-3)-(6(y+1)-3)=0

We get rid of parentheses

6y+y-(6(y+1)-3)-3=0



We calculate terms in parentheses: -(6(y+1)-3), so:

6(y+1)-3

We multiply parentheses

6y+6-3

We add all the numbers together, and all the variables

6y+3

Back to the equation:

-(6y+3)



We add all the numbers together, and all the variables

7y-(6y+3)-3=0

We get rid of parentheses

7y-6y-3-3=0

We add all the numbers together, and all the variables

y-6=0

We move all terms containing y to the left, all other terms to the right

y=6

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